Electron Configuration for Samarium

Electron Configuration for Samarium

The electron configuration of Samarium is [Xe] 4f6 6s2. Samarium is a rare earth element that belongs to the Lanthanide series.

It is known by the symbol Sm and has an atomic number of 62. A Swedish chemist by the name of Carl Gustaf Mosander made the first discovery of it in 1853. Samarium is used in various applications, such as in the production of carbon-arc lighting, as a neutron absorber in nuclear reactors, and in the manufacturing of superconducting materials.

Additionally, its compounds are used as catalysts in organic synthesis. Samarium has a melting point of 1074°C and a boiling point of 1803°C. Its electron configuration is [Xe] 4f6 6s2. You will learn more about the electron configuration of samarium and its properties.

What Are the Steps for Determining Electron Configuration For Samarium?

To determine the electron configuration for Samarium, you need to follow a specific order of filling orbitals with electrons. The atomic number of Samarium is 62, so its electron configuration is written as 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 4f6 6s2.

When it comes to determining the electron configuration for samarium, there are a few easy steps that you can follow. It is important to understand each step so that you can write out the electron configuration correctly. Here are the steps you need to follow to determine the electron configuration for Samarium:

Electron Configuration for Samarium
Electron Configuration for Samarium

Step 1: Find The Atomic Number Of Samarium

The first step in determining the electron configuration for Samarium is to find its atomic number. The atomic number for Samarium is 62, which means it has 62 electrons in total.

Step 2: Write The Configuration For The Previous Noble Gas

The next step is to write the configuration for the previous noble gas. In Samarium’s case, the previous noble gas is Xenon (atomic number 54). The electron configuration for Xenon is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6. You can write this configuration in shorthand notation as [Xe].

Step 3: Write The Subshell Configuration For The Remaining Electrons

After writing the configuration for the previous noble gas, you need to write the subshell configuration for the remaining electrons in Samarium. Samarium has 62 electrons, and the configuration for Xenon accounts for 54 of those electrons. This means that there are 8 electrons left, which can be written out using the subshell configuration notation.

Step 4: Complete The Configuration With Remaining Electrons

The final step is to complete the configuration with the remaining electrons, using the subshell configuration notation. Samarium has 8 electrons left, which can be written as 5d1 6s2 4f5. When you combine this subshell notation with the previous noble gas notation [Xe], you get the full electron configuration for Samarium, which is [Xe] 4f5 6s2 5d1. In conclusion, determining the electron configuration for Samarium is straightforward if you follow the steps listed above. It involves finding the atomic number, writing the configuration for the previous noble gas, writing the subshell configuration for the remaining electrons, and completing the configuration with the remaining electrons.

Electron Configuration for Samarium
Electron Configuration for Samarium

 

Frequently Asked Questions On Electron Configuration For Samarium

What Element Has The Electron Configuration 1s2 2s2 2p6 3s2 3p6 4s2?

The element with this electron configuration is a neutral atom of calcium (Ca).

What Is The Electron Configuration Of 1s 2 2s 2 2p 6 3s 2 3p 5?

The electron configuration of 1s 2 2s 2 2p 6 3s 2 3p 5 is: 1s 2 2s 2 2p 6 3s 2 3p 5. This configuration represents an atom with 17 electrons, with 2 electrons in the first energy level, 8 in the second, and 7 in the third.

The last number, 3p5, refers to the number of electrons in the outermost energy level.

What Is the Electron Configuration of Berkelium?

The electron configuration of berkelium is [Rn] 5f9 7s2.

What Is The Electronic Configuration Of An Element 1s2 2s2 2p6 3s2 3p5?

The electronic configuration of an element referred to as 1s2 2s2 2p6 3s2 3p5 indicates that it has 5 electrons in its outermost shell, with a total of 18 electrons distributed at various energy levels. It belongs to the phosphorus family, and its atomic number is 33. Google maps

Conclusion

To summarize, Samarium has an electron configuration of [Xe]4f6 6s2, with six valence electrons in the 4f subshell. Its unique properties make it useful in a variety of applications, such as in the production of samarium-cobalt magnets and as a neutron absorber in nuclear reactors.

Understanding the electron configuration of samarium can provide insight into its behavior and reactivity in these different contexts. Keep exploring the fascinating world of chemistry and the intricacies of electron configurations for even more insightful knowledge.

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